WebJul 1, 2014 · Solution. Step 1. First use stoichiometry to solve for the number of moles of CO 2 produced. (2molC 2H 6)( 4molCO 22molC 2H 6) = 4molCO 2. So 4 moles of Carbon Dioxide are produced if we react 2 moles of ethane gas. Step 2. Now we simply need to manipulate the ideal gas equation to solve for the variable of interest. WebWhen Sal converts the mass of glucose to moles of glucose using its molar mass, he gets 0.139 mols. Glucose is related to the other chemicals by a 6:1 ratio using the balanced chemical equation. So the number of moles for oxygen, water, and carbon dioxide will be six times whatever the number of mols of glucose is (0.139 x 6 = 0.833). Hope that ...
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WebWrite a balanced equation to show the reaction of gaseous ethane with gaseous oxygen to form carbon monoxide gas and water vapor. C2H6 (g)+7 O (g) → 2 CO2 (g)+3 H2O (g)C2H6 (g)+7 O (g) → 2 CO2 (g)+3 H2O (g) C2H6 (g)+5 O (g) → 2 CO (g)+3 H2O (g)C2H6 (g)+5 O (g) → 2 CO (g)+3 H2O (g) WebApr 21, 2024 · The enthalpy of combustion of ethane gas, C2H6 (g), is about -1.5*103 kJ/mol. When ethane reacts with O2 (g), the products are carbon dioxide CO2 (g) and water H2O (l). How much heat is released during the combustion of ethane gas when 14 mols of O2 (g) are consumed. Express your answer in kJ. Follow • 2 Add comment Report 1 … my age till today
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WebWe allow 51 g of oxygen to react with 39 g of ethane. The reaction is shown below. Since the heat of combustion of ethane is -1560 kJ/mol (per mole of C 2 H 6), how much heat is exchanged by the system if the reaction is the system? C 2 H 6 (g) + 7272 O 2 (g) →→ 2 CO 2 (g) + 3 H 2 O (g) WebNotice that more molecules. of oxygen are needed to balance the equation for ethane, because the alkane contains more hydrogen atoms which need to be oxidised to form water molecules. Question WebWhat is the balanced equation of kclo3 KCl O2? We shall balance the number of oxygen atoms by cross-multiplying the number of oxygen atoms in the product and reactant side. Then, we shall balance the potassium atoms by multiplying 2 to KCl in the product side. The balanced equation is given as: $ 2KCl{O_3} \to 2KCl + 3{O_2} $. how to paint over red